(7V^2+2V-5)+(V^2-2V-3)=

Solution for (7V^2+2V-5)+(V^2-2V-3)= equation:

Simplifying
(7V2 + 2V + -5) + (V2 + -2V + -3) = 0

Reorder the terms:
(-5 + 2V + 7V2) + (V2 + -2V + -3) = 0

Remove parenthesis around (-5 + 2V + 7V2)
-5 + 2V + 7V2 + (V2 + -2V + -3) = 0

Reorder the terms:
-5 + 2V + 7V2 + (-3 + -2V + V2) = 0

Remove parenthesis around (-3 + -2V + V2)
-5 + 2V + 7V2 + -3 + -2V + V2 = 0

Reorder the terms:
-5 + -3 + 2V + -2V + 7V2 + V2 = 0

Combine like terms: -5 + -3 = -8
-8 + 2V + -2V + 7V2 + V2 = 0

Combine like terms: 2V + -2V = 0
-8 + 0 + 7V2 + V2 = 0
-8 + 7V2 + V2 = 0

Combine like terms: 7V2 + V2 = 8V2
-8 + 8V2 = 0

Solving
-8 + 8V2 = 0

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 8V2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 8V2 = 0 + 8
8V2 = 0 + 8

Combine like terms: 0 + 8 = 8
8V2 = 8

Divide each side by '8'.
V2 = 1

Simplifying
V2 = 1

Take the square root of each side:
V = {-1, 1}